Generalised Linear Models essay writing services
GLM Coursework 2014/15
Deadline Friday 20th March 3pm (not 4pm)
Twenty tobacco budworm moths of each sex were exposed to different doses of the insecticide trans-cypermethrin. The numbers of budworm moths killed during a 3-day exposure were as follows for each sex (male, female) and dose level in mg’s.
num.killed | sex | dose | |
1 | 1 | male | 1 |
2 | 4 | male | 2 |
3 | 9 | male | 4 |
4 | 13 | male | 8 |
5 | 18 | male | 16 |
6 | 20 | male | 32 |
7 | 0 | female | 1 |
8 | 2 | female | 2 |
9 | 6 | female | 4 |
10 | 10 | female | 8 |
11 | 12 | female | 16 |
12 | 16 | female | 32 |
Type the data into R as follows. Press Enter at the end of each line including blank lines.
num.killed <- scan()
1 4 9 13 18 20 0 2 6 10 12 16
sex <- scan()
0 0 0 0 0 0 1 1 1 1 1 1
dose <- scan()
1 2 4 8 16 32 1 2 4 8 16 32
Fit two models by doing the following.
ldose <- log(dose)/log(2) #convert to base-2 log dose ldose #have a look
y <- cbind(num.killed, 20-num.killed) #add number survived fit1 <- glm(y ~ ldose * sex, family=binomial(link=probit))
fit2 <- glm(y ~ sex + ldose, family=binomial(link=probit))
You may also run the following lines and refer to the chi-square distribution table.
anova(fit1,test=”Chisq”)
summary(fit2)
No other R commands are allowed.
Hand in your answers to the following for assessment.
- What model is fitted in fit1? Write it formally and define all the terms. [4]
- How is the model in fit2 differ from that in fit1? [2]
- Does the model in fit1 fit the data adequately? Use deviance to answer this question. [2]
- Can the model in fit1 be simplified to the model in fit2? Use change in deviance to answer this question. [2]
- Can sex be removed from the model in fit2? Use change in deviance to answer this ques- tion. [2]
- What are the maximum likelihood estimates of the parameters of the additive model? What are their standard errors? Test the significance of each parameter using its estimate and standard error. [4]
- How does the probability of a kill change with log dose and sex of the budworm moth accord- ing to the additive model? [4]
Warning. The coursework must be your own. Handing in an edited version of someone else’s answers may result in zero marks for all parties and even disciplinary action.
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SA Coursework 2014/15
Deadline Friday 20 March 3pm (not 4pm)
(a) Derive the survival function S (t ) of a lifetime T ∼ E x p (λ). Find − log S (t ) and comment on it. (b) Calculate the Kaplan-Meier estimate for each group in the following.
Treatment Group:
6,6,6,6*,7,9*,10,10*,11*,13,16,17*,19*,20*,22,23,25*,32*,32*,34*,35
Control Group (no treatment):
1,1,2,2,3,4,5,5,8,8,8,8,11,11,12,15,17,22,23
Note that * indicates right censored data.
(c) Use the log rank test to compare the two groups of lifetimes.
All the answers should be obtained by hand. Calculators may be used. Some intermediate steps should be included. You may check your answers using R, but do not hand in any R output.
Warning. The coursework must be your own. Handing in an edited version of someone else’s answers may result in zero marks for all parties and even disciplinary action.
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